Vue 递归多级菜单的实例代码

[
 {
 name: "About",
 path: "/about",
 children: [
  {
  name: "About US",
  path: "/about/us"
  },
  {
  name: "About Comp",
  path: "/about/pany",
  children: [
   {
   name: "About Comp A",
   path: "/about/pany/A",
   children: [
    {
    name: "About Comp A 1",
    path: "/about/pany/A/1"
    }
   ]
   }
  ]
  }
 ]
 },
 {
 name: "Link",
 path: "/link"
 }
];

// Menuitem

<template>
 <li class="item">
 <slot />
 </li>
</template>

<!-- Menu -->

<template>
 <ul class="wrapper">
 <!-- 遍历 router 菜单数据 -->
 <menuitem :key="index" v-for="(item, index) in router">
  <!-- 对于没有 children 子菜单的 item -->
  <span class="item-title" v-if="!item.children">{{item.name}}</span>

  <!-- 对于有 children 子菜单的 item -->
  <template v-else>
  <span @click="handleToggleShow">{{item.name}}</span>
  <!-- 递归操作 -->
  <menu :router="item.children" v-if="toggleShow"></menu>
  </template>
 </menuitem>
 </ul>
</template>

<script>
 import MenuItem from "./MenuItem";

 export default {
 name: "Menu",
 props: ["router"], // Menu 组件接受一个 router 作为菜单数据
 ponents: { MenuItem },
 data() {
  return {
  toggleShow: false // toggle 状态
  };
 },
 methods: {
  handleToggleShow() {
  // 处理 toggle 状态的是否展开子菜单 handler
  this.toggleShow = !this.toggleShow;
  }
 }
 };
</script>

<template>
 <div class="home">
 <menu :router="router"></menu>
 </div>
</template>

<script>
 import Menu from '@/ponents/Menu.vue'

 export default {
 name: 'home',
 ponents: {
  Menu
 },
 data () {
  return {
  router: // ... 省略菜单数据
  }
 }
 }
</script>

<style lang="stylus" scoped>
 .item {
 margin: 10px 0;
 padding: 0 10px;
 border-radius: 4px;
 list-style: none;
 background: skyblue;
 color: #fff;
 }
</style>

<style lang="stylus" scoped>
 .wrapper {
 cursor: pointer;

 .item-title {
  font-size: 16px;
 }
 }
</style>